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📅 April 15, 2026 👤 scraface

Apr 15, 2026

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📌 Now, we count the number of favorable outcomes where Gorilla X and Gorilla Y are both on the same day. There are two cases:

📌 Case 1:** Both X and Y are on Monday.

📌 Then we must choose 1 more gorilla from the remaining 4 to join them:

📌 \binom{4}{1} = 4

📌 Case 2:** Both X and Y are on Tuesday.

📌 Then the 3 gorillas on Monday must be chosen from the remaining 4:

📌 \binom{4}{3} = 4

📌 Thus, the total number of favorable outcomes is:

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Total amount: \( A = P (1 + r/n)^{nt} \)
\( A = 10,000 (1 + 0.004167)^{36} pprox 10,000 (1.1616) pprox 11,616...
#### 11,6161. A rectangle has a length that is twice its width, and it...
Perimeter \( = 2( ext{length} + ext{width}) = 2(2w + w) = 6w \).
Given perimeter is 48, so \( 6w = 48 \).
Solving for \( w \), we get \( w = rac{48}{6} = 8 \).
Area \( = ext{length} imes ext{width} = 16 imes 8 = 128 \).
A quadratic equation \( ax^2 + bx + c = 0 \) has roots 3 and -2. If \(...
Using Vieta's formulas:
Sum of roots \( = -rac{b}{a} = 3 + (-2) = 1 \).

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