As \( t \to \infty \), the term \( e^-0.1(t-5) \to 0 \). Thus, the denominator approaches 1:

As \( t \to \infty \), the term \( e^-0.1(t-5) \to 0 \). Thus, the denominator approaches 1: - Sterling Industries

📅 April 18, 2026 👤 scraface

Apr 18, 2026

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