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A physics teacher explains kinetic energy: \( KE = \frac{1}{2}mv^2 \). If a 1200 kg car speeds up from 10 m/s to 30 m/s, by how much does its kinetic energy increase?
Initial KE: \( \frac{1}{2} \cdot 1200 \cdot 10^2 = 600 \cdot 100 = 60,000 \) J
Final KE: \( \frac{1}{2} \cdot 1200 \cdot 30^2 = 600 \cdot 900 = 540,000 \) J

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