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Home » Dividiendo ambos lados entre 20, obtenemos \( x = \frac200020 = 100 \). - Sterling Industries

Dividiendo ambos lados entre 20, obtenemos \( x = \frac200020 = 100 \). - Sterling Industries

📅 April 18, 2026 👤 scraface

Apr 18, 2026

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Perpendicularity condition: $ \vec{OG} \cdot (\vec{OA} + \vec{OB}) = 0...
Magnitude condition: $ \sqrt{(3m)^2 + (4n)^2} = 5 \implies 9m^2 + 16n^...
From $ 9m + 16n = 0 $, solve $ m = -\frac{16}{9}n $. Substitute into t...
9\left(\frac{256}{81}n^2\right) + 16n^2 = \frac{256}{9}n^2 + 16n^2 = \...
Thus $ n^2 = \frac{25 \cdot 9}{400} = \frac{225}{400} = \frac{9}{16} \...
If $ n = \frac{3}{4} $, $ m = -\frac{16}{9} \cdot \frac{3}{4} = -\frac...
Check $ \vec{OG} \cdot (\vec{OA} + \vec{OB}) = 0 $: Both cases satisfy...
\boxed{\left( -\dfrac{4}{3}, \dfrac{3}{4} \right)}
Question: The maximum imaginary part of a root of $ z^5 + z^3 + z + 1...
Solution: Factor the polynomial:

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