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Home » Égaliser les exposants donne \( x + 1 = 5 \). - Sterling Industries

Égaliser les exposants donne \( x + 1 = 5 \). - Sterling Industries

📅 April 17, 2026 👤 scraface

Apr 17, 2026

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oxed{rac{5}{2}}.
Question: A hydrologist models the flow resistance $ R $ through a por...
R = rac{p + q}{p - q} + rac{p - q}{p + q} - 2,
where $ p > q > 0 $ are hydraulic conductivity parameters. Find the mi...
Solution: Let $ a = rac{p + q}{p - q} $ and $ b = rac{p - q}{p + q}...
R = a + rac{1}{a} - 2.
Define $ f(a) = a + rac{1}{a} - 2 $ for $ a > 1 $. By AM-GM, $ a + r...
R = rac{(p+q)^2 + (p-q)^2}{(p-q)(p+q)} - 2 = rac{p^2 + 2pq + q^2 + p...
R = 2\left( rac{p^2 + q^2}{p^2 - q^2} - 1
ight) = 2\left( rac{2q^2}{p^2 - q^2}

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