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📅 April 16, 2026 👤 scraface

Apr 16, 2026

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\( P(1) = k(1)^2 + m(1) + n = 120 \implies k + m + n = 120 \)
\( P(2) = k(2)^2 + m(2) + n = 150 \implies 4k + 2m + n = 150 \)
\( P(3) = k(3)^2 + m(3) + n = 210 \implies 9k + 3m + n = 210 \)
Set up the system:
k + m + n &= 120 \quad \text{(1)}\\
4k + 2m + n &= 150 \quad \text{(2)}\\
9k + 3m + n &= 210 \quad \text{(3)}
Subtract (4) from (5):
Substitute \( k = 15 \) into (4):
3(15) + m = 30 \implies 45 + m = 30 \implies m = -15

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