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Home » I. Microtubule minuendo at poles - Sterling Industries

I. Microtubule minuendo at poles - Sterling Industries

📅 April 17, 2026 👤 scraface

Apr 17, 2026

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Solution: The central angle corresponding to the arc is $ 120^\circ $,...
c = 2R \sin\left(rac{ heta}{2}
Substituting $ heta = rac{2\pi}{3} $:
c = 2R \sin\left(rac{\pi}{3}
ight) = 2R \cdot rac{\sqrt{3}}{2} = R\sqrt{3}
The ratio of chord length to radius is:
rac{c}{R} = \sqrt{3}
Thus, the ratio is $ oxed{\sqrt{3}} $.
Question: An environmental researcher models a circular carbon capture...
Solution: For an equilateral triangle with side $ s $, the circumradiu...

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