FÃ¼r $ x = 1 $: $ x \mid y \Rightarrow y \mid 1 $ â‡’ $ y = \pm1 $, aber $ y \mid 1 $: nur $ y = \pm1 $. $ y \mid x $? $ \pm1 \mid 1 $: wahr â‡’ Implikation wahr. $ x \mid 0 $? wahr â‡’ Implikation wahr.

Sat, 18 Apr 2026 10:16:57 +0000

Content under review