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A_{\text{new}} = \frac{\sqrt{3}}{4} \times 8^2 = \frac{\sqrt{3}}{4} \times 64 = 16\sqrt{3} \text{ cm}^2
The decrease in area is:
\Delta A = A_{\text{original}} - A_{\text{new}} = 25\sqrt{3} - 16\sqrt{3} = 9\sqrt{3} \text{ cm}^2

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