Question: In a right triangle, the radius of the circumscribed circle is 13 cm, and the radius of the inscribed circle is 5 cm. What is the area of the triangle?

Mon, 20 Apr 2026 20:18:45 +0000

**1. Intro: A Hidden Geometry Mystery in Every US Classroom – and Beyond**
Curious minds are increasingly diving into the intersection of math, real-world geometry, and digital learning trends. Recent spikes in search volume reveal growing interest in why geometric properties like circumcircle and incircle radii connect so meaningfully to triangle dimensions. This profile explores a compelling question: In a right triangle, the circumradius is 13 cm and the inradius is 5 cm—what is the area? Intriguing patterns behind right triangle geometry continue to spark curiosity, especially among students, educators, and self-learners navigating math concepts with clarity and precision. This triangle’s story isn’t just geometric—it’s a gateway to deeper problem-solving skills in a data-driven age. **2. Why This Question Is Rising—Trends in Math Education and Digital Inquiry**
The growing attention around this triangle question reflects broader shifts in how Americans engage with math concepts online. With mobile-first browsing habits and rising demand for visual, digestible learning, users seek concise answers that explain not just formulas, but relationships between triangle parts. Search trends show rising intent: users aren’t just looking for an answer—they’re pursuing understanding through real-world applications. The fusion of geometry with practical problem-solving aligns with current educational focuses on critical thinking, logic, and real-life math relevance. This query taps into both curiosity and learning goals, making it highly aligned with Discover’s intent-driven algorithms. **3. How In a Right Triangle, R = 13 cm and r = 5 cm Unlocks the Area**
In right triangles, a key relationship exists between the circumradius, inradius, and area. The circumradius \( R = \frac{c}{2} \), where \( c \) is the hypotenuse. Here, \( R = 13 \) cm gives \( c = 26 \) cm. Meanwhile, the inradius \( r = \frac{a + b - c}{2} \), linking the legs \( a \) and \( b \). Substituting values and using the area formula \( A = \frac{1}{2}ab \), along with Pythagorean theorem and inradius formula, leads to a solvable equation. Solving step-by-step reveals how the geometry flows naturally—no shortcut, just clear logic rooted in fundamental triangle properties. **4. Common Questions and Answers That Build Confidence**
Many learners wonder:
- How exactly do circumradius and inradius link in right triangles?
- Can area be calculated directly from these values, or does it require solving equations?
- What numeric answer emerges from this combination?
The circumradius confirms \( c = 26 \) cm. Using the identity \( r = \frac{a + b - c}{2} = 5 \), leads to \( a + b = 36 \). With \( a^2 + b^2 = 26^2 = 676 \), solving the system yields \( ab = 312 \), so area is \( \frac{1}{2} \cdot ab = 156 \) cm². These clear steps build trust—proving that complex relationships yield solid, repeatable results.