Thus, \( t = 3 \) or \( t = 2 \). Since \( \sqrt{v} = t \), the roots \( v \) are \( v = 3^2 = 9 \) and \( v = 2^2 = 4 \). The product of the roots is:

Wed, 22 Apr 2026 11:32:33 +0000

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