So indeed, as $x \to 0^+$ or $x \to \frac\pi2^-$, the expression grows without bound.

So indeed, as $x \to 0^+$ or $x \to \frac\pi2^-$, the expression grows without bound. - Sterling Industries

📅 April 18, 2026 👤 scraface

Apr 18, 2026

Content is being prepared. Please check back later.