A retired engineer is helping students build a bridge model. The bridge must span 60 cm and is supported by triangular trusses. Each truss forms an isosceles triangle with a base of 12 cm. If the two equal sides are each 13 cm, what is the height of each truss from the base to the apex?

Fri, 17 Apr 2026 03:22:33 +0000

A retired engineer is helping students build a bridge model. The bridge must span 60 cm and is supported by triangular trusses standing on isosceles designs. Each triangular truss has a base of 12 cm, with two equal sides measuring 13 cm. This blend of classic geometry and hands-on learning is sparking growing interest across the US, especially as STEM education emphasizes real-world problem solving. Students and parents alike are drawn to projects that turn abstract math into tangible results—like understanding structural stability through careful shape analysis. Cultural and educational trends highlight a renewed focus on practical engineering insights at all ages. The retired engineer’s hands-on guidance simplifies complex trigonometry and physics for learners navigating basic structural design. This approach resonates deeply with families seeking meaningful, screen-friendly STEM activities that build both skill and confidence—without relying on sensationalism. Each truss forms an isosceles triangle with a base of 12 cm and equal sides of 13 cm. Though the triangle spans a short base, it reaches a clean apex above the deck, illustrating how geometry supports load distribution efficiently. Students can calculate the height—the vertical distance from base to top—using a straightforward method based on splitting the base in half and applying the Pythagorean theorem. H3: Calculating the Truss Height—Step by Step
The 12 cm base is split evenly into two 6 cm segments by the tallest height. Each side triangle forms two right-angled halves. Using the formula a² + b² = c², where c = 13 cm (the equal side), and a = 6 cm (half the base), solve for height b:
13² = 6² + b²
169 = 36 + b²
b² = 133
b ≈ √133 ≈ 11.53 cm