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Home » Therefore, no such vector $\mathbfv$ exists. - Sterling Industries

Therefore, no such vector $\mathbfv$ exists. - Sterling Industries

📅 April 15, 2026 👤 scraface

Apr 15, 2026

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The word "PROBABILITY" has:
Vowels: O, A, I, I (4 vowels, with I repeated)
Consonants: P, R, B, B, L, T, Y (7 consonants, with B repeated)
Treat vowels as a single unit ("block"):
The vowels form a block, so we now arrange:
7 consonants
Total units = 1 + 7 = 8
Arrange the 8 units (with repeated consonants):
The number of arrangements of these 8 units, accounting for repeated B...
\frac{8!}{2!} = \frac{40320}{2} = 20160

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