Thus, the rate of volume increase at $ \theta = 60^\circ $ is $ \boxed{\frac{k\sqrt3}2} $.

Thus, the rate of volume increase at $ \theta = 60^\circ $ is $ \boxed{\frac{k\sqrt3}2} $. - Sterling Industries

📅 April 18, 2026 👤 scraface

Apr 18, 2026

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