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Home » Why Every Student Needs JD 11 Mastery—CEE Saves the Day! - Sterling Industries

Why Every Student Needs JD 11 Mastery—CEE Saves the Day! - Sterling Industries

📅 April 16, 2026 👤 scraface

Apr 16, 2026

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16x^4 - 81y^4 = (4x^2)^2 - (9y^2)^2 = (4x^2 - 9y^2)(4x^2 + 9y^2)
Now notice that $ 4x^2 - 9y^2 $ is also a difference of squares:
4x^2 - 9y^2 = (2x - 3y)(2x + 3y)
So the full factorization is:
Final answer: $ \boxed{(2x - 3y)(2x + 3y)(4x^2 + 9y^2)} $
Question: Compute the square of $ 3\sqrt{2} - 2\sqrt{3} $.
Use the identity $ (a - b)^2 = a^2 - 2ab + b^2 $:
Compute each term:
2(3\sqrt{2})(2\sqrt{3}) = 12\sqrt{6}
Final answer: $ \boxed{30 - 12\sqrt{6}} $

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